Hello Aspirants
We are providing you with Quantitative Aptitude Section Mock for the upcoming IBPS Clerk and RBI Assistant 2017 Prelim Exam. It contains 35 questions and time limit is 22 minutes.
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Question 1 of 35
1. Question
1 pointsA man borrows Rs. 5000 at 10% compound rate of interest. At the end of each year he pays back Rs. 1000. How much amount should he pay at the end of the third year to clear all his dues?
Correct
After one year amount = 5000 *110/100 =5500
He pays 1000 back, so remaining 5500-1000=4500
After two year amount =4500* 110/100 = 4950
He pays 1000 back, so remaining 4950-1000=3950.
After three year amount = 3950*110/100 =4345
He pays 1000 back, so remaining 4345 -1000=3345.Incorrect
After one year amount = 5000 *110/100 =5500
He pays 1000 back, so remaining 5500-1000=4500
After two year amount =4500* 110/100 = 4950
He pays 1000 back, so remaining 4950-1000=3950.
After three year amount = 3950*110/100 =4345
He pays 1000 back, so remaining 4345 -1000=3345.Unattempted
After one year amount = 5000 *110/100 =5500
He pays 1000 back, so remaining 5500-1000=4500
After two year amount =4500* 110/100 = 4950
He pays 1000 back, so remaining 4950-1000=3950.
After three year amount = 3950*110/100 =4345
He pays 1000 back, so remaining 4345 -1000=3345. -
Question 2 of 35
2. Question
1 pointsNaresh got married 10 years ago. His present age is 6/5 times his age at the time of his marriage Naresh’s sister was 15years younger to him at the time of his marriage. The present age of Suresh’s sister is
Correct
Naresh’s age at the time of his marriage = X years
X + 10 = 6/5 X
X = 50.
Present age of Naresh = 60
Naresh’s Sister age = 60 – 15 = 45 yearsIncorrect
Naresh’s age at the time of his marriage = X years
X + 10 = 6/5 X
X = 50.
Present age of Naresh = 60
Naresh’s Sister age = 60 – 15 = 45 yearsUnattempted
Naresh’s age at the time of his marriage = X years
X + 10 = 6/5 X
X = 50.
Present age of Naresh = 60
Naresh’s Sister age = 60 – 15 = 45 years -
Question 3 of 35
3. Question
1 pointsA’s age 5 years ago and B’s 5 years hence is same. Also the present ages of A and B are in the ratio 5 : 3. Find the ratio of A’s age 5 years hence to B’s age 5 years ago.
Correct
Let A’s present age = 5x, and B’s = 3x
A’s age 5 years ago to B’s age 5 years hence is same
So (5x-5) = (3x+5)
Solve x = 5
So A’s present age = 25, and B’s = 15
Required ratio = (25+5) : (15-5)
=30 : 10 ==> 3:1Incorrect
Let A’s present age = 5x, and B’s = 3x
A’s age 5 years ago to B’s age 5 years hence is same
So (5x-5) = (3x+5)
Solve x = 5
So A’s present age = 25, and B’s = 15
Required ratio = (25+5) : (15-5)
=30 : 10 ==> 3:1Unattempted
Let A’s present age = 5x, and B’s = 3x
A’s age 5 years ago to B’s age 5 years hence is same
So (5x-5) = (3x+5)
Solve x = 5
So A’s present age = 25, and B’s = 15
Required ratio = (25+5) : (15-5)
=30 : 10 ==> 3:1 -
Question 4 of 35
4. Question
1 pointsThere is sufficient food for 372men for 36days. After 15days, 120men left the place. For how many days will the rest of the food last for the rest of the men.
Correct
372*36 = 15*372 + 252(372-120) *x
X=31days
Alternate method
372 * 21 (36-15) = 252 (372-120)*x
372*21 = 252 *x
X=31daysIncorrect
372*36 = 15*372 + 252(372-120) *x
X=31days
Alternate method
372 * 21 (36-15) = 252 (372-120)*x
372*21 = 252 *x
X=31daysUnattempted
372*36 = 15*372 + 252(372-120) *x
X=31days
Alternate method
372 * 21 (36-15) = 252 (372-120)*x
372*21 = 252 *x
X=31days -
Question 5 of 35
5. Question
1 pointsThe length of a plot is five times its breath. A playground measuring 400 square meters occupies one fifth of the total area of a plot. What is the length of the plot in meter?
Correct
Area of the plot = (5 x 400) m2
=2000 m2
B=x
L=5x
Area =x*5x = 2000
5x 2 =2000
x 2 400
x=20m
L=5*20=100mIncorrect
Area of the plot = (5 x 400) m2
=2000 m2
B=x
L=5x
Area =x*5x = 2000
5x 2 =2000
x 2 400
x=20m
L=5*20=100mUnattempted
Area of the plot = (5 x 400) m2
=2000 m2
B=x
L=5x
Area =x*5x = 2000
5x 2 =2000
x 2 400
x=20m
L=5*20=100m -
Question 6 of 35
6. Question
1 pointsDirections: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
I. 3x2 – 5x – 12 = 0,
II. 3y2 + 22y + 24 = 0Correct
x = -4/3, 3
y = -6, -4/3Incorrect
x = -4/3, 3
y = -6, -4/3Unattempted
x = -4/3, 3
y = -6, -4/3 -
Question 7 of 35
7. Question
1 pointsDirections: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
I. 3x2 – 7x – 6 = 0,
II. 3y2 + 20y + 25 = 0Correct
x = -2/3, 3
y = -5, -5/3Incorrect
x = -2/3, 3
y = -5, -5/3Unattempted
x = -2/3, 3
y = -5, -5/3 -
Question 8 of 35
8. Question
1 pointsDirections: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
I. 2x2+25x + 78 = 0,
II. 3y2 + 23y + 30 = 0Correct
x = -13/2, -6
y = -6, -5/3Incorrect
x = -13/2, -6
y = -6, -5/3Unattempted
x = -13/2, -6
y = -6, -5/3 -
Question 9 of 35
9. Question
1 pointsDirections: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
I. 4x2 – x – 14 = 0,
II. 2y2 – 13y + 20 = 0Correct
x = -7/4, 2
y = 5/2, 4Incorrect
x = -7/4, 2
y = 5/2, 4Unattempted
x = -7/4, 2
y = 5/2, 4 -
Question 10 of 35
10. Question
1 pointsDirections: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
I. 3x2 + 8x + 4 = 0,
II. 2y2 – 7y – 4 = 0Correct
x = -2/3, -2
y = 4, -1/2Incorrect
x = -2/3, -2
y = 4, -1/2Unattempted
x = -2/3, -2
y = 4, -1/2 -
Question 11 of 35
11. Question
1 pointsDirections: What approximate value should come in place of the x in the following questions? (You are not expected to calculate exact values)
2449.98 + 1270.09 – 67.059% of 2299.974 = x
Correct
Incorrect
Unattempted
-
Question 12 of 35
12. Question
1 pointsDirections: What approximate value should come in place of the x in the following questions? (You are not expected to calculate exact values)
37.94% of 450.0925 – 45.022% of 259.902 = x% of 599.938
Correct
Incorrect
Unattempted
-
Question 13 of 35
13. Question
1 pointsDirections: What approximate value should come in place of the x in the following questions? (You are not expected to calculate exact values)
468 + 405 ÷ 17 – 17.03% of 465 = x
Correct
Incorrect
Unattempted
-
Question 14 of 35
14. Question
1 pointsDirections: What approximate value should come in place of the x in the following questions? (You are not expected to calculate exact values)
470 ÷ 18 + 17.08 × 35.98 – 79 = x
Correct
Incorrect
Unattempted
-
Question 15 of 35
15. Question
1 pointsDirections: What approximate value should come in place of the x in the following questions? (You are not expected to calculate exact values)
√1370 + 59.009 × 32.09% of 249.99 = x
Correct
Incorrect
Unattempted
-
Question 16 of 35
16. Question
1 pointsDirections (1 – 5): A survey is taken in 6 cities of a state. The pie chart shows the distribution of people in each city with total 8,40,000 people.
Number of people in city B is how much percent greater than the number of people in city D?
Correct
A = 117600, B = 201600, C = 109200, D= 134400, E = 100800, F = 176400
So here – [(201600-134400)/134400] × 100 = 50%Incorrect
A = 117600, B = 201600, C = 109200, D= 134400, E = 100800, F = 176400
So here – [(201600-134400)/134400] × 100 = 50%Unattempted
A = 117600, B = 201600, C = 109200, D= 134400, E = 100800, F = 176400
So here – [(201600-134400)/134400] × 100 = 50% -
Question 17 of 35
17. Question
1 pointsDirections (1 – 5): A survey is taken in 6 cities of a state. The pie chart shows the distribution of people in each city with total 8,40,000 people.
What is the total number of people in cities C, E and F?
Correct
A = 117600, B = 201600, C = 109200, D= 134400, E = 100800, F = 176400
Incorrect
A = 117600, B = 201600, C = 109200, D= 134400, E = 100800, F = 176400
Unattempted
A = 117600, B = 201600, C = 109200, D= 134400, E = 100800, F = 176400
-
Question 18 of 35
18. Question
1 pointsDirections (1 – 5): A survey is taken in 6 cities of a state. The pie chart shows the distribution of people in each city with total 8,40,000 people.
What is the ratio between number of people in cities F and C together and that in B and E together?
Correct
A = 117600, B = 201600, C = 109200, D = 134400, E = 100800, F = 176400
176400 + 109200 : 201600 + 100800
2856 : 3024
17 : 18Incorrect
A = 117600, B = 201600, C = 109200, D = 134400, E = 100800, F = 176400
176400 + 109200 : 201600 + 100800
2856 : 3024
17 : 18Unattempted
A = 117600, B = 201600, C = 109200, D = 134400, E = 100800, F = 176400
176400 + 109200 : 201600 + 100800
2856 : 3024
17 : 18 -
Question 19 of 35
19. Question
1 pointsDirections (1 – 5): A survey is taken in 6 cities of a state. The pie chart shows the distribution of people in each city with total 8,40,000 people.
If there are 65% males in city B, 49% males in city D and 47% males in city A, then females in these cities form what percent of total number of people in these three cities?
Correct
Females in B, D, and A = 35/100 × 201600 + 51/100 × 134400 + 53/100 × 100800 = 192528
So % = [192528/(201600+134400+100800)] × 100 = 44.08%Incorrect
Females in B, D, and A = 35/100 × 201600 + 51/100 × 134400 + 53/100 × 100800 = 192528
So % = [192528/(201600+134400+100800)] × 100 = 44.08%Unattempted
Females in B, D, and A = 35/100 × 201600 + 51/100 × 134400 + 53/100 × 100800 = 192528
So % = [192528/(201600+134400+100800)] × 100 = 44.08% -
Question 20 of 35
20. Question
1 pointsDirections (1 – 5): A survey is taken in 6 cities of a state. The pie chart shows the distribution of people in each city with total 8,40,000 people.
Number of people in city A is what percent of the number of people in city C?
Correct
Required % = 14/13 × 100 = 107.69%
Incorrect
Required % = 14/13 × 100 = 107.69%
Unattempted
Required % = 14/13 × 100 = 107.69%
-
Question 21 of 35
21. Question
1 pointsDirections: What will come in place of question mark (?) in the following number series which follow a certain pattern.
4, 27, 46, 63, 76, ?
Correct
+23, +19, +17, +13, +11
Incorrect
+23, +19, +17, +13, +11
Unattempted
+23, +19, +17, +13, +11
-
Question 22 of 35
22. Question
1 pointsDirections: What will come in place of question mark (?) in the following number series which follow a certain pattern.
8, 6, 9, 23, 87, ?
Correct
*1 – 2, *2 – 3, *3 – 4, *4 – 5, *5 – 6
Incorrect
*1 – 2, *2 – 3, *3 – 4, *4 – 5, *5 – 6
Unattempted
*1 – 2, *2 – 3, *3 – 4, *4 – 5, *5 – 6
-
Question 23 of 35
23. Question
1 pointsDirections: What will come in place of question mark (?) in the following number series which follow a certain pattern.
33, 17, 16, 34, ?, 1064
Correct
*0.5 + 0.5, *1 – 1, *2 + 2, *4 -4, *8 + 8
Incorrect
*0.5 + 0.5, *1 – 1, *2 + 2, *4 -4, *8 + 8
Unattempted
*0.5 + 0.5, *1 – 1, *2 + 2, *4 -4, *8 + 8
-
Question 24 of 35
24. Question
1 pointsDirections: What will come in place of question mark (?) in the following number series which follow a certain pattern.
190, 94, 46, 22, ?, 4
Correct
190 – 2 = 188/2 = 94
94 – 2 = 92, 92/2 = 46
46 – 2 = 44, 44/2 = 22
22 – 2 = 20, 20/2 = 10Incorrect
190 – 2 = 188/2 = 94
94 – 2 = 92, 92/2 = 46
46 – 2 = 44, 44/2 = 22
22 – 2 = 20, 20/2 = 10Unattempted
190 – 2 = 188/2 = 94
94 – 2 = 92, 92/2 = 46
46 – 2 = 44, 44/2 = 22
22 – 2 = 20, 20/2 = 10 -
Question 25 of 35
25. Question
1 pointsDirections: What will come in place of question mark (?) in the following number series which follow a certain pattern.
125, 124, 127, 120, 135, ?
Correct
-1, +3, -7, +15, -31
Incorrect
-1, +3, -7, +15, -31
Unattempted
-1, +3, -7, +15, -31
-
Question 26 of 35
26. Question
1 pointsA two-digit number is such that it is three more than six times the sum of the digits. If the number formed by reversing the digits is three less than five times the sum of the digits, what is the unit digit of the number?
Correct
Cannot be determined
Incorrect
Cannot be determined
Unattempted
Cannot be determined
-
Question 27 of 35
27. Question
1 pointsA and B entered into a partnership investing Rs. 15000 and Rs. 10000 respectively. After 4 months, A withdrew Rs. 5000 while B invested Rs. 5000 more. After 4 more months C joins the business with a capital of Rs. 20000. The share of B exceeds that of A, out of a total profit of Rs. 28500 after one year by
Correct
A: B: C = 15000*4 + 10000*8 : 10000*4 + 15000*8 : 20000*4
=140: 160 : 80 ==> 7:8:4
Difference of B and A’s shares
=28500(8/19 -7/19)
=28500 * 1/19
= Rs. 1500Incorrect
A: B: C = 15000*4 + 10000*8 : 10000*4 + 15000*8 : 20000*4
=140: 160 : 80 ==> 7:8:4
Difference of B and A’s shares
=28500(8/19 -7/19)
=28500 * 1/19
= Rs. 1500Unattempted
A: B: C = 15000*4 + 10000*8 : 10000*4 + 15000*8 : 20000*4
=140: 160 : 80 ==> 7:8:4
Difference of B and A’s shares
=28500(8/19 -7/19)
=28500 * 1/19
= Rs. 1500 -
Question 28 of 35
28. Question
1 pointsA Shopkeeper sells two articles at Rs.1000 each, making a profit of 40% on the first article and a loss of 40% on the second article. Find the net Profit or loss that he makes(approx.)?
Correct
SP of first article = Rs.1000
Profit = 40%
CP*140/100=1000
CP=5000/7
SP of Second Article = Rs.1000
Loss = 40%
CP*60/100 =1000
CP=5000/3
Total SP=2000. CP=(5000/7 + 5000/3) ==>50000/21=2380
As the CP is more than SP, he makes a loss.
Loss = CP – SP = 2380- 2000 = 380
So, Loss Percent =(380/2380) *100
=16%Incorrect
SP of first article = Rs.1000
Profit = 40%
CP*140/100=1000
CP=5000/7
SP of Second Article = Rs.1000
Loss = 40%
CP*60/100 =1000
CP=5000/3
Total SP=2000. CP=(5000/7 + 5000/3) ==>50000/21=2380
As the CP is more than SP, he makes a loss.
Loss = CP – SP = 2380- 2000 = 380
So, Loss Percent =(380/2380) *100
=16%Unattempted
SP of first article = Rs.1000
Profit = 40%
CP*140/100=1000
CP=5000/7
SP of Second Article = Rs.1000
Loss = 40%
CP*60/100 =1000
CP=5000/3
Total SP=2000. CP=(5000/7 + 5000/3) ==>50000/21=2380
As the CP is more than SP, he makes a loss.
Loss = CP – SP = 2380- 2000 = 380
So, Loss Percent =(380/2380) *100
=16% -
Question 29 of 35
29. Question
1 pointsThere are two pipes which are functioning simultaneously to fill a tank in 12 hours, if one pipe fills the tank 10 hours faster than other then how many hours second pipe will take to fill the tank?
Correct
If the first pipe fill the tank in X hours,
So, second pipe will fill the tank in X + 10 hrs.
1/x + 1/(x+10) =1/12
2x+10/x(x+10) =1/12
X2 – 14x-120=0
X=20
2nd Pipe 20+10=30hrIncorrect
If the first pipe fill the tank in X hours,
So, second pipe will fill the tank in X + 10 hrs.
1/x + 1/(x+10) =1/12
2x+10/x(x+10) =1/12
X2 – 14x-120=0
X=20
2nd Pipe 20+10=30hrUnattempted
If the first pipe fill the tank in X hours,
So, second pipe will fill the tank in X + 10 hrs.
1/x + 1/(x+10) =1/12
2x+10/x(x+10) =1/12
X2 – 14x-120=0
X=20
2nd Pipe 20+10=30hr -
Question 30 of 35
30. Question
1 pointsA motorboat went the river for 14 km and then up the river for 9 km. If took a total of 5 hrs the entire journey. Find the speed of the river flow if the speed of the boat in still water is 5 km/h.
Correct
Let the speed of the stream be x km/hr.
Then upstream 5-x
Downstream 5+x
14/(5+x) + 9/(5-x) =5
14(5-x)+9(5+x)/(5+x)(5-x)
x = 2km/hr.Incorrect
Let the speed of the stream be x km/hr.
Then upstream 5-x
Downstream 5+x
14/(5+x) + 9/(5-x) =5
14(5-x)+9(5+x)/(5+x)(5-x)
x = 2km/hr.Unattempted
Let the speed of the stream be x km/hr.
Then upstream 5-x
Downstream 5+x
14/(5+x) + 9/(5-x) =5
14(5-x)+9(5+x)/(5+x)(5-x)
x = 2km/hr. -
Question 31 of 35
31. Question
1 pointsDirections: What value should come in place of the x in the following questions?
1615 ÷ 19 – 12 × 27 + 45% of 1240 = x
Correct
Incorrect
Unattempted
-
Question 32 of 35
32. Question
1 pointsDirections: What value should come in place of the x in the following questions?
√1156 + √3025 + x% of 650 = 167
Correct
Incorrect
Unattempted
-
Question 33 of 35
33. Question
1 pointsDirections: What value should come in place of the x in the following questions?
√2916 + 38% of 450 – 12 × x = 21
Correct
Incorrect
Unattempted
-
Question 34 of 35
34. Question
1 pointsDirections: What value should come in place of the x in the following questions?
√(36 × 41 – 24% of 750) = x
Correct
Incorrect
Unattempted
-
Question 35 of 35
35. Question
1 pointsDirections: What value should come in place of the x in the following questions?
54% of 650 + 45 × 32 – 165 = x
Correct
Incorrect
Unattempted
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Need to work hard.
mam plz check Q19 and Q35th should be “54% of 650
yes, 49% males in city D not females
ok. and its city E nt A..in solutn tkn A…and ans 44.08%.
and mam some doubt in Q23 series..0.5 1 2 3 4 .. 3 how? logic explain plz.. if increase 1 thn its should be 1.5.. and if no double thn 3 why?
yes it should double
You have reached 20 of 35 points, (57.14%)
yay.mam now i improved..
thax 4 quizz
@mod
@Shubhra_AspirantsZone:disqus
yes ??
24/25
100 likes
17/17
Thnks AC
Question no.3 explain plz
A-4 = B + 5
So A – B = 9 ………(1)
Also, A/B = 5/3 ………..(2)
Find A and B
Final answer = (A+5)/(B-5)
Waha 4ke badle 5 minus kiya hai
A-5=b+5!!! Aise….
Ok. Yes 5 years ago
Question mai 5 yr ago hoga ya ans Mai
Plz clarify
In Question, check Q again
Car – A covers a distance of 448 km in 8 hours and car – B covers 110 km distance more than car – A in 9 hours.What is the ratio between the speed of car A and car B respectively?
Ma’am please Help…
speed of A 448/8 =56
speed of B 558/9 =62
A : B = 28 : 31
this is my attempt, If you found ans is wrong please inform me.
Ur answer is correct…
thanks madam
Keep practicing…
ATB
thanks, if my expl is right please mention,
Yes correct hai.
ok.
wrong ex A-5=b+5
A -5 =B +5
A = B+ 10
A/B =5/3
3A =5B
3(B+10)= 5B
B = 15
A = 25
A+5 : B-5 = 30 : 10 = 3:1 may be
question no 2 pa eak full stop lagao sir.
Mam, Ques no 28?
doubt cleared
marks board kaha hai?
11 marks only
I do agree with all of the ideas you’ve presented in your post. They’re very convincing and will definitely work. Still, the posts are very short for starters. Could you please extend them a bit from next time? Thanks for the post.